(5x-1)^2/5=7

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Solution for (5x-1)^2/5=7 equation:


x in (-oo:+oo)

((5*x-1)^2)/5 = 7 // - 7

((5*x-1)^2)/5-7 = 0

((5*x-1)^2)/5+(-7*5)/5 = 0

(5*x-1)^2-7*5 = 0

25*x^2-10*x-34 = 0

25*x^2-10*x-34 = 0

25*x^2-10*x-34 = 0

DELTA = (-10)^2-(-34*4*25)

DELTA = 3500

DELTA > 0

x = (3500^(1/2)+10)/(2*25) or x = (10-3500^(1/2))/(2*25)

x = (10*35^(1/2)+10)/50 or x = (10-10*35^(1/2))/50

(x-((10-10*35^(1/2))/50))*(x-((10*35^(1/2)+10)/50)) = 0

((x-((10-10*35^(1/2))/50))*(x-((10*35^(1/2)+10)/50)))/5 = 0

((x-((10-10*35^(1/2))/50))*(x-((10*35^(1/2)+10)/50)))/5 = 0 // * 5

(x-((10-10*35^(1/2))/50))*(x-((10*35^(1/2)+10)/50)) = 0

( x-((10*35^(1/2)+10)/50) )

x-((10*35^(1/2)+10)/50) = 0 // + (10*35^(1/2)+10)/50

x = (10*35^(1/2)+10)/50

( x-((10-10*35^(1/2))/50) )

x-((10-10*35^(1/2))/50) = 0 // + (10-10*35^(1/2))/50

x = (10-10*35^(1/2))/50

x in { (10*35^(1/2)+10)/50, (10-10*35^(1/2))/50 }

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